LED AND RESISTOR CIRCUIT

Session 2, MLQ 2.4. Current can be measured across the resistor using V=IR, and Kirchoff's Second Law to calculate V: Battery voltage = 12V Voltage drop across an LED = 0.737V Voltage across R1 = (12 - 0.737). I = (12-0.737)/470 = 23.963mA. Note that, of course, when the voltage is positive, no current passes through LED2. When the voltage is reversed (i.e., is negative), no current passes through LED1. Which means that the modulus value of the voltage is the same, regardless of the direction of the voltage. Therefore, the modulus value of the current will be the same, regardless of the direction of the voltage. Whether the current is positive or negative will be the only difference in its value, and this will correspond to whether the voltage is positive or negative. So, for a positive voltage, the current will be positive; for a negative voltage, the current will be negative. In both cases, the modulus value of the current will be the same.