The circuit is an impedance converter using a back-to-back voltage-controlled current sources (VCIS). This specific circuit uses only a resistor at port 2.
Input Impedance:
Iin = -Gm2 · V2
Iin = -Gm2 [-(Gm1 · V1)(Z2)]
Iin = Gm1 · Gm2 · Z2 · V1
Iin = Gm1 · Gm2 · Z2 · Vin
Zin = Vin/Iin
Zin = 1 / (Gm1 · Gm2 · Z2)
Zin = [1 / (Gm1 · Gm2)] · (1 / Z2)
The driving circuit at port 1 sees a scaled reciprocal of the impedance at port 2. The scaling factor is the reciprocal of the product of the transconductances of the two VCISs.
For the saved values,
Zin = 1 / [(25 mA/V)(4 mA/V)(200 Ω)]
Zin = 1 / (20,000 µA·Ω/V²)
Zin = 1 / (20 mA/V) = 1 / (0.02 A/V)
Zin = 50 Ω
The resistance of 200 Ω at port 2 is seen as a 50 Ω resistance at port 1, this causes a 20 mA current for a 1 V input voltage.
The reciprocal of resistance is conductance, the scaling factor [1 / (Gm1 · Gm2)] converts the conductance back to resistance.
Voltage Gain:
Vout = -(Gm1 · Vin)(R)
Vout = -(25 mA/V · Vin)(200 Ω)
Vout = -5 · Vin
Av = Vout/Vin = -5
For the saved input of 1 V, the voltage developed at port 2 is -5 V.
The voltage gain can be made positive by reversing the output current directions of the two VCISs. This will not affect the input impedance.
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