Charging A Capacitor Having An Initial Voltage Through A Diode And Resistor In Series
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Charging A Capacitor Having An Initial Voltage Through A Diode And Resistor In Series.
Simplified equation by treating the diode voltage drop as constant
t = R·C · ln [(Vs - Vd - Vc0) / (Vs - Vd - Vc)]
Vs = source voltage
Vc = capacitor voltage as a function of time
Vd = diode voltage drop
Vc0 = initial capacitor voltage
Creator
GGoodwin
1116 Circuits
Date Created
5 years, 4 months ago
Last Modified
5 years, 2 months ago
Tags
Open Circuit
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